Yippeeee - a long weekend which gives me a chance to relax, and even update. 
I'm at least as tired of giving health updates as you are no doubt tired of reading them. So this time I've chosen a story problem for all you geeks, nerds and others already bored by the prospects of having no more exams to study for (for ever or for awhile).
Suppose a guy who likes to drink scotch has a number of empty Oban containers and decides to use them to organize his loose change. He begins to fill one container with pennies, another with nickels, and a third with dimes. How rich will he be when they are all full of coins?
I actually started doing this very experiment, but have since become bored with the whole procedure. And I also suspect my cleaning lady has been siphoning off some of the nickels and dimes, but not having a precise mark of how full the containers were, it's difficult to prove.
So if anyone wants to get a bunch of friends together to solve these problems, I'd love to find out the answer. You get to drink the scotch and then contribute all your spare change and then count the coins at the end. Sounds like fun, right?
Or you could weigh the empty and full containers, subtract and then divide by the weight of a single coin. More math but less counting involved.
Or you can calculate the results using your knowledge of geometry - and packing efficiency of discs into a cylindrical volume. There may be helpful information somewhere on the internet for the latter.
Helpful information: especially for those of you who live in other countries with other currencies.
Oban container is approximately 314 mm high and 81.5 mm in diameter.
One penny = US$0.01 (= about 0.00785 euro) 19.05 mm diameter by 1.55 mm high (and weighs 2.500 grams)
One nickel = US$0.05 and is 21.21 mm in diameter and 1.95 mm high (5.00 grams)
One dime = US$0.10 and is 17.91 mm in diameter and 1.35 mm high (2.268 grams)
For a hint.
I'm at least as tired of giving health updates as you are no doubt tired of reading them. So this time I've chosen a story problem for all you geeks, nerds and others already bored by the prospects of having no more exams to study for (for ever or for awhile).
Suppose a guy who likes to drink scotch has a number of empty Oban containers and decides to use them to organize his loose change. He begins to fill one container with pennies, another with nickels, and a third with dimes. How rich will he be when they are all full of coins?
I actually started doing this very experiment, but have since become bored with the whole procedure. And I also suspect my cleaning lady has been siphoning off some of the nickels and dimes, but not having a precise mark of how full the containers were, it's difficult to prove.
So if anyone wants to get a bunch of friends together to solve these problems, I'd love to find out the answer. You get to drink the scotch and then contribute all your spare change and then count the coins at the end. Sounds like fun, right?
Or you could weigh the empty and full containers, subtract and then divide by the weight of a single coin. More math but less counting involved.
Or you can calculate the results using your knowledge of geometry - and packing efficiency of discs into a cylindrical volume. There may be helpful information somewhere on the internet for the latter.
Helpful information: especially for those of you who live in other countries with other currencies.
Oban container is approximately 314 mm high and 81.5 mm in diameter.
One penny = US$0.01 (= about 0.00785 euro) 19.05 mm diameter by 1.55 mm high (and weighs 2.500 grams)
One nickel = US$0.05 and is 21.21 mm in diameter and 1.95 mm high (5.00 grams)
One dime = US$0.10 and is 17.91 mm in diameter and 1.35 mm high (2.268 grams)
For a hint.
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hahaha
wats up???
im in holland, but feel very anxious today...im a bit an anxious person sometimes..damn!!!!!